0=16x^2-6x-10

Solution for 0=16x^2-6x-10 equation:

0=16x^2-6x-10

We move all terms to the left:

0-(16x^2-6x-10)=0

We add all the numbers together, and all the variables

-(16x^2-6x-10)=0

We get rid of parentheses

-16x^2+6x+10=0

a = -16; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·(-16)·10
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*-16}=\frac{20}{-32}
=-5/8
$